PottaFella Posted September 29, 2017 Report Share Posted September 29, 2017 Maths never my strong point, so a bit confused about shrinkage (I really shouldn't be) but when I threw some mugs recently I thought I'd sized them correctly wet but they ended up too big, they did not shrink enough... So, if my stoneware clay has a shrinkage rate of say 12%, if I made my pot 114mm high x 114mm wide, I'd end up with a pot approx 100mm x 100mm – is that right? Also, how much shrinkage should one expect at bisque (say 1050 degrees C) and how much between bisque and fully fired? Link to comment Share on other sites More sharing options...
Sputty Posted September 29, 2017 Report Share Posted September 29, 2017 . Link to comment Share on other sites More sharing options...
neilestrick Posted September 29, 2017 Report Share Posted September 29, 2017 If the shrinkage rate is 12%, then the finished size is 88% of the wet size. So to do the math, just take the finished size and divide it by 0.88 and that will give you the wet size. Link to comment Share on other sites More sharing options...
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